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x^2-47x+546=0
a = 1; b = -47; c = +546;
Δ = b2-4ac
Δ = -472-4·1·546
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-5}{2*1}=\frac{42}{2} =21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+5}{2*1}=\frac{52}{2} =26 $
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